How do you write the equation of a line that is perpendicular to the given line and that passes through the given point: y-4=5/2(x+3); (-7,8)?

Answer 1

#y=-2/5x+26/5#

#y-4=5/2 (x+3)#
#2y-8=5x+15#
#2y=5x+23#
#y=5/2x+23/2#

if it is perpendicular then when you multiply the gradients together you get -1

so the gradient of the new line is #-2/5#
The line is of the form #y=-2/5x+c# but we know it passes through (-7,8) so if we put these values in we will get the equation.
#8=-2/5xx-7+c#
#8=14/5+c#
#c=5 1/5#
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Answer 2

To find the equation of a line perpendicular to the given line, you need to use the fact that perpendicular lines have slopes that are negative reciprocals of each other. First, find the slope of the given line by rearranging the equation into slope-intercept form (y = mx + b), where m is the slope. Then, find the negative reciprocal of this slope to get the slope of the perpendicular line. Next, use the point (-7,8) to find the y-intercept (b) of the perpendicular line. Finally, plug the slope and y-intercept into the slope-intercept form equation (y = mx + b) to get the equation of the perpendicular line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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