How do you write the equation of a line that has a slope of -2 and passes through (3, -1)?

Answer 1

#y=-2x+5#

Use slope-intercept form or point-slope form. Here, I will use slope-intercept form.

#y=mx+b#

Solve for b using the slope, m, and the (x,y) points of (3,-1).

#y=-2x+b#
#-1=(-2*3)+b#
#-1=-6+b#
#b=-1+6=5#
#y=-2x+5#
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Answer 2

The equation of a line with slope m passing through point (x₁, y₁) is given by the point-slope form: y - y₁ = m(x - x₁). Substituting the given values, the equation becomes y - (-1) = -2(x - 3). Simplify to get the equation in slope-intercept form: y + 1 = -2x + 6. Further simplifying yields the equation: y = -2x + 5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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