How do you write the equation of a line in slope intercept, point slope and standard form given (-2,0) and (3,-4)?

Answer 1

Answers are explained below.

Slope of the line joining these two points is #(-4-0)/(3+2) = (-4)/5#
Point slope form is y-0= #(-4)/5 (x+2)#
Solve this equation for y, #y= (-4)/5 x -8/5#. This is the slope intercept form

Simplify the above equation, by eliminating the denominator and bring both variable on left side and the constant on the right side.

So, 4x+ 5y=-8 is the standard form

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Answer 2

Slope-intercept form: ( y = mx + b ) Point-slope form: ( y - y_1 = m(x - x_1) ) Standard form: ( Ax + By = C )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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