How do you write the equation of a line in slope intercept, point slope and standard form given Point: (5, -6) Slope: m = 1?
A "point" is conventionally written as an (x,y) coordinate. Thus, the x = 5 and the y = -6 in this case. Plug those values and the given slope into the equation for a line:
y = m*x + b
This will also allow you to solve for the line intercept, 'b' and write the general equation for any x and y.
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Slope-intercept form: y = mx + b Point-slope form: y - y1 = m(x - x1) Standard form: Ax + By = C
Substituting the given slope and point into the equations:
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Slope-intercept form: y = 1x + b -6 = 1(5) + b b = -11 y = x - 11
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Point-slope form: y - (-6) = 1(x - 5) y + 6 = x - 5
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Standard form: x - y = -11
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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