How do you write the equation of a line in point slope form that is parallel to #y=2/3x+9# and goes through (4,8)?
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To write the equation of a line in point-slope form that is parallel to ( y = \frac{2}{3}x + 9 ) and passes through the point (4, 8), you use the slope of the given line, which is ( \frac{2}{3} ), and the given point. Then, you use the point-slope formula ( y - y_1 = m(x - x_1) ), where ( (x_1, y_1) ) is the given point and ( m ) is the slope. Substituting the values gives: ( y - 8 = \frac{2}{3}(x - 4) ). Therefore, the equation of the line in point-slope form is ( y - 8 = \frac{2}{3}(x - 4) ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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