How do you write the equation of a line in point slope form that is parallel to #y=2/3x+9# and goes through (4,8)?

Answer 1
The answer is #y=2/3x+16/3#
The function we are looking form is a linear function, so it can be written as #y=ax+b#. The line is parallel to #y=2/3x+9# so #a=2/3# (If 2 lines are parallel their #a# coefficients are equal). Now we have to calculate #b# knowing that the line goes through #(4,8)# so you can substitute 4 for #x# and 8 for #y# and solve the equation for #b#.
The equation is #8=2/3*4+b#, so #b=8-2/3*4# #b=24/3-8/3# #b=16/3#
So the final answer is #y=2/3x+16/3#
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Answer 2

To write the equation of a line in point-slope form that is parallel to ( y = \frac{2}{3}x + 9 ) and passes through the point (4, 8), you use the slope of the given line, which is ( \frac{2}{3} ), and the given point. Then, you use the point-slope formula ( y - y_1 = m(x - x_1) ), where ( (x_1, y_1) ) is the given point and ( m ) is the slope. Substituting the values gives: ( y - 8 = \frac{2}{3}(x - 4) ). Therefore, the equation of the line in point-slope form is ( y - 8 = \frac{2}{3}(x - 4) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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