How do you write the equation of a line in point slope form that is parallel to #y=-7x+1# and goes through (-1/2, -1/3)?
Line (1): y1 = -7x + 1. Line y2, parallel to y1 must have slope same slope: -7.
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To write the equation of a line in point-slope form that is parallel to ( y = -7x + 1 ) and goes through ( (-\frac{1}{2}, -\frac{1}{3}) ), you use the formula:
[ y - y_1 = m(x - x_1) ]
where ( m ) is the slope of the given line (since the new line is parallel), and ( (x_1, y_1) ) are the coordinates of the given point.
First, identify the slope of the given line, which is ( -7 ). Then, substitute the slope and the coordinates of the given point into the formula:
[ y - (-\frac{1}{3}) = -7(x - (-\frac{1}{2})) ]
Simplify the equation to get it into point-slope form:
[ y + \frac{1}{3} = -7(x + \frac{1}{2}) ]
This is the equation of the line in point-slope form.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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