How do you write the equation of a line in point slope form that is parallel to #y=-7x+1# and goes through (-1/2, -1/3)?

Answer 1

Line (1): y1 = -7x + 1. Line y2, parallel to y1 must have slope same slope: -7.

#y2 = -7x + b.# Find b.
y2 passing at point #(-1/2, -1/3)# gives the equation:
#-1/3 = -7(-1/2) + b -> b = -1/3 - 7/2 = -23/6#
Answer: # y = -7x - 23/6#
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Answer 2

To write the equation of a line in point-slope form that is parallel to ( y = -7x + 1 ) and goes through ( (-\frac{1}{2}, -\frac{1}{3}) ), you use the formula:

[ y - y_1 = m(x - x_1) ]

where ( m ) is the slope of the given line (since the new line is parallel), and ( (x_1, y_1) ) are the coordinates of the given point.

First, identify the slope of the given line, which is ( -7 ). Then, substitute the slope and the coordinates of the given point into the formula:

[ y - (-\frac{1}{3}) = -7(x - (-\frac{1}{2})) ]

Simplify the equation to get it into point-slope form:

[ y + \frac{1}{3} = -7(x + \frac{1}{2}) ]

This is the equation of the line in point-slope form.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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