How do you write the equation of a line in point slope form into slope intercept form given #y - 1/2 = x + 1/2#?

Answer 1
Point-slope form for a linear equation is #(y-haty) = m(x-hatx)# for a line with slope #m# through the point #(hatx,haty)#
#y-1/2 = x+1/2# can easily be converted into this form #(y-1/2) = (1)(x-(-1/2))# for a line with a slope of #1# through the point #(-1/2,+1/2)#
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Answer 2

To write the equation of a line in point-slope form into slope-intercept form, you rearrange the equation to solve for y. Start by isolating y on one side of the equation and simplifying the expression to put it in the form y = mx + b, where m represents the slope and b represents the y-intercept.

Given the equation y - 1/2 = x + 1/2, add 1/2 to both sides to isolate y. This yields y = x + 1. Therefore, the equation in slope-intercept form is y = x + 1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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