How do you write the equation of a line given (-4,6) (-1,-3)?
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To write the equation of a line given two points ((x_1, y_1)) and ((x_2, y_2)), you can first find the slope using the formula (m = \frac{{y_2 - y_1}}{{x_2 - x_1}}). Once you have the slope, you can use one of the points and the slope in the point-slope form equation (y - y_1 = m(x - x_1)). Finally, you can simplify the equation to standard form (Ax + By = C).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you write an equation in standard form given that the line has slope -2 and y-intercept of 2?
- How do you write the equation of the line that passes through the point (6, -2) and has a slope of -2/3?
- What is the slope of the line perpendicular to 2y= -6x +8?
- How do you write an equation in point slope form when slope is #1/3# and the y- intercept is –4?
- How do you write an equation for the line in slope intercept form that is parallel to the given line and that passes through the given point y = x + 9; (–1, 3)?

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