How do you write the equation in standard form with Slope 5; through (-3, -9)?
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The equation of a line in slope-intercept form is (y = mx + b), where (m) is the slope and (b) is the y-intercept. To write the equation in standard form, which is (Ax + By = C), where (A), (B), and (C) are integers and (A) is positive, we need to rearrange the equation.
First, substitute the given slope ((m = 5)) and point (((-3, -9))) into the slope-intercept form equation:
(y = 5x + b)
Then, substitute the coordinates of the point ((-3, -9)) into the equation and solve for (b):
(-9 = 5(-3) + b)
Simplify:
(-9 = -15 + b)
Add (15) to both sides to solve for (b):
(b = 6)
Now, substitute the slope (m = 5) and the y-intercept (b = 6) into the slope-intercept form equation:
(y = 5x + 6)
To convert to standard form, move (5x) to the left side:
(5x - y = -6)
Multiply all terms by -1 to make the coefficient of (x) positive:
(-5x + y = 6)
Therefore, the equation of the line in standard form with a slope of (5) passing through the point ((-3, -9)) is (-5x + y = 6).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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