How do you write the equation in slope intercept form given (4,1):(5,3)?

Answer 1

#y=2x-7#

#"the equation of a line in "color(blue)"slope-intercept form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))# #"where m represents the slope and b, the y-intercept"#
#"to calculate the slope use the " color(blue)"gradient formula"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))# #"where " (x_1,y_1),(x_2y_2)" are 2 coordinate points"#
#"the 2 points here are " (4,1)" and " (5,3)#
#"let " (x_1,y_1)=(4,1)" and " (x_2,y_2)=(5,3)#
#rArrm=(3-1)/(5-4)=2/1=2#
#rArry=2x+b#
#"to find b, substitute either of the given points into the"# #"equation and solve for b"#
#"using " (4,1)#
#1=(2xx4)+b#
#rArrb=1-8=-7#
#rArry=2x-7larrcolor(red)" in slope-intercept form"#
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Answer 2

First, calculate the slope using the formula: ( \text{slope} = \frac{{y_2 - y_1}}{{x_2 - x_1}} ). Then, use one of the given points and the slope to write the equation in slope-intercept form ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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