How do you write the equation in point slope form given (8,7), (-2,-4)?

Answer 1

#y+4=11/10(x+2).# [#pt.(-2,-4) used]

#y-7=11/10(x-8).# [using #pt.(8,7)

Let the given pts. be #A(8,7), B(-2,-4).#
Then, by defn., slope of line #AB# is, by defn., #(y_B-y_A)/(x_B-x_A)= (-4-7)/(-2-8)=-11/-10=11/10.#
Pt. #B(-2,-4)# ies on Line #AB#
Hence, eqn. of line #AB,# in slope-pt. form, using pt.#B(-2,-4),# is :
#y-(-4)=11/10(x-(-2)),# i.e., #y+4=11/10(x+2).#
One can choose pt.#A(8,7)# to get the eqn. #y-7=11/10(x-8).#
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Answer 2

To write the equation in point-slope form given the points (8,7) and (-2,-4), you can use the formula:

y - y1 = m(x - x1)

Where (x1, y1) is one of the points and m is the slope, which can be found using the formula:

m = (y2 - y1) / (x2 - x1)

Substitute the coordinates into the formulas to find the equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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