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How do you write the equation given slope 2 and passes through (-2,-5)?

Answer 1

Kennedy Adams

The answer is in point slope form.

#2x-y-1=0#

#(y-y_1)=m(x-x_1)#

#(y-(-5))=2(x-(-2))#

#y=2x-(-4)+(-5)#

#y=2x-1#

#2x-y-1=0#

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Answer 2

Genesis Allen

#y=2x-1#

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"here "m=2#

#rArry=2x+blarrcolor(blue)"is the partial equation"#

#"to find b substitute "(-2,-5)# #"into the partial equation"#

#-5=-4+brArrb=-5+4=-1#

#rArry=2x-1larrcolor(red)"in slope-intercept form"#

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Answer 3

Jace Anderson

The equation of a line given its slope ((m)) and a point ((x_1, y_1)) it passes through is given by the point-slope form:

[ y - y_1 = m(x - x_1) ]

Given (m = 2) and the point ((-2, -5)), we can substitute these values into the equation:

[ y - (-5) = 2(x - (-2)) ] [ y + 5 = 2(x + 2) ]

Expanding and simplifying:

[ y + 5 = 2x + 4 ] [ y = 2x - 1 ]

So, the equation of the line is (y = 2x - 1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.