How do you write the electron configuration of tin?

Answer 1

#Sn:# #1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(10)4p^(6)4d^(10)5s^(2)5p^2#

For tin, #Z=50#..........
And thus 50 electrons must be distributed according to the usual #"aufbau"# scheme...........Tin lies in Group 14, and thus should have a similar electronic configuration to carbon. Can you demonstrate the similarity.

Many thanks to Michael for pointing out a mistake.

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Answer 2

The electron configuration of tin is: 1s^2 2s^2 2p^6 3s^2 3p^6 3d^10 4s^2 4p^6 4d^10 5s^2 5p^2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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