How do you write in standard form of y= 8x + 4?

Answer 1

#8x-y=-4#

#"the equation of a line in "color(blue)"standard form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#
#"where A is a positive integer and B, C are integers"#
#"rearrange "y=8x+4" into this form"#
#"subtract "y" from both sides"#
#0=8x-y+4#
#"subtract 4 from both sides"#
#8x-y=-4larrcolor(red)"in standard form"#
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Answer 2

To write the equation ( y = 8x + 4 ) in standard form, you move all the terms involving variables to one side of the equation and the constant to the other side. In this case, subtract ( 8x ) from both sides to get ( -8x + y = 4 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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