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How do you write # f(x) = x^2 - 3x + 1# in vertex form?

Answer 1

Eva Abramson

In vertex form #f(x)=(x-3/2)^2-5/4# Vertex is #(3/2,-5/4)#

#f(x)=x^2-3x+1= (x^2-3x+9/4)-9/4+1=(x-3/2)^2-5/4# Vertex =#(3/2,-5/4)# graph{x^2-3x+1 [-10, 10, -5, 5]}[Ans]

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Answer 2

Nathan Axel

To write the function ( f(x) = x^2 - 3x + 1 ) in vertex form, complete the square. First, factor out the leading coefficient (if not 1), then complete the square for the quadratic term. The vertex form of a quadratic function is ( f(x) = a(x - h)^2 + k ), where (h, k) is the vertex of the parabola. The formula for completing the square for ( ax^2 + bx ) is ( \left(x + \frac{b}{2a}\right)^2 - \frac{b^2}{4a} ). Apply these steps to rewrite the function in vertex form.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.