How do you write equation of a line goes through the point (4,-14) (2,-5)?

Answer 1

#2y+9x-8=0#

Find the gradient

#m= "change in y"/ "change in x"#
#m = (-5 - (-14))/(2-4) = -9/2#

Use the equation:

#y-y_1 = m(x-x_1)#
Substitute the values from any coordinate, #(4,-14)# or #(2,-5)#
#y-(-5)=-9/2(x-2)#
#y+5=-9/2(x-2)#
Get rid of the fraction by multiplying both sides by #2# and expand the brackets:
#2y+10=-9x+18#

And you get the equation:

#2y+9x-8=0#
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Answer 2

To write the equation of a line passing through two points (x1, y1) and (x2, y2), you first find the slope using the formula: slope = (y2 - y1) / (x2 - x1). Then, you choose one of the points and use the point-slope form: y - y1 = m(x - x1), where m is the slope and (x1, y1) is one of the points. Plugging in the values and simplifying gives you the equation of the line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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