How do you write and solve an inequality represents the values of x for which the area of the rectangle will be at least 35 square feet?

Answer 1

#x >= 35/w# where #w > 0# is the width of the rectangle (assuming #x# is the length)

There really is not enough information here. You have not indicated how #x# is related to the rectangle.
Perhaps (as an alternative to the assumption I made [above]), you meant for #x > 0# to be the length of one side of a square. In this case: #color(white)("XXX")x^2 >= 35# #color(white)("XXX")rarr x >=sqrt(35)#
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Answer 2

To write and solve an inequality representing the values of ( x ) for which the area of the rectangle will be at least 35 square feet, you use the formula for the area of a rectangle: ( A = l \times w ), where ( l ) represents the length and ( w ) represents the width. Therefore, the inequality is ( A \geq 35 ). Substituting the formula for area, we get ( l \times w \geq 35 ). Since the length and width must both be positive values, the inequality can be expressed as ( x \times w \geq 35 ). Then, solve for ( x ) to find the values that satisfy the inequality.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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