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How do you write an equation with slope of -3 and x-intercept of 3?

Answer 1

Hazel Anglin

#3x+y-9=0#

The form is x = y/(slope)+(x-intercept) on par with the usual

y = x (slope) + (y-intercept) form

Here, this becomes

#x =-y/3+3# that givesr

#3x+y-9=0#

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Answer 2

Abigail Allen

To write the equation of a line given its slope ((m)) and x-intercept ((a)), you can use the slope-intercept form:

[ y = mx + b ]

Given the slope ((m = -3)) and the x-intercept ((a = 3)), we can substitute these values into the equation:

[ y = -3x + b ]

To find the y-intercept ((b)), we use the fact that the x-intercept occurs when (y = 0):

[ 0 = -3(3) + b ] [ 0 = -9 + b ] [ b = 9 ]

So, the equation of the line is (y = -3x + 9).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.