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How do you write an equation that contains points (4, -1) and (-2, -13)?

Answer 1

Genesis Allen

#y=2x-9#

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"to calculate m use the "color(blue)"gradient formula"#

#•color(white)(x)m=(y_2-y_1)/(x_2-x_1)#

#"let "(x_1,y_1)=(4,-1)" and "(x_2,y_2)=(-2,-13)#

#rArrm=(-13-(-1))/(-2-4)=(-12)/(-6)=2#

#rArry=2x+blarrcolor(blue)"is the partial equation"#

#"to find b substitute either of the 2 given points into"# #"the partial equation"#

#"using "(4,-1)" then"#

#-1=8+brArrb=-1-8=-9#

#rArry=2x-9larrcolor(red)"is equation of line"#

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Answer 2

Savannah Anderson

To write an equation that contains the points (4, -1) and (-2, -13), you can first find the slope using the formula:

slope = (change in y) / (change in x)

Then, use the point-slope form of the equation of a line:

y - y₁ = m(x - x₁)

where (x₁, y₁) is one of the given points and m is the slope. After substituting the values of one of the points and the slope, you can simplify to find the equation of the line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.