How do you write an equation that contains points (-2, -3) and is perpendicular to 5x-2y=8?
Writing it in Slope-intercept form,
Equation of line passing through (-2,-3) with slope -(2/5) is
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To write an equation that contains the point (-2, -3) and is perpendicular to (5x - 2y = 8), first find the slope of the given line by rearranging the equation into slope-intercept form (y = mx + b). Then, determine the negative reciprocal of this slope to find the slope of the perpendicular line. Finally, use the point-slope form (y - y_1 = m(x - x_1)) with the given point (-2, -3) and the slope of the perpendicular line to write the equation.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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