How do you write an equation that contains points (-2, -3) and is perpendicular to 5x-2y=8?

Answer 1

#color(brown)(2x + 5y = -19#

Given equation is #5x - 2y = 8#

Writing it in Slope-intercept form,

#y = (5/2)x - 4#
Slope of the line #m = (5/2)#
Slope of the perpendicular line #-(1/m) = -(2/5)#

Equation of line passing through (-2,-3) with slope -(2/5) is

#y + 3 = -(2/5) * (x + 2)#
#5y + 15 = -2x - 4#
#color(brown)(2x + 5y = -19#
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Answer 2

To write an equation that contains the point (-2, -3) and is perpendicular to (5x - 2y = 8), first find the slope of the given line by rearranging the equation into slope-intercept form (y = mx + b). Then, determine the negative reciprocal of this slope to find the slope of the perpendicular line. Finally, use the point-slope form (y - y_1 = m(x - x_1)) with the given point (-2, -3) and the slope of the perpendicular line to write the equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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