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How do you write an equation of the line with slope 3/7 containing the point (3,8)?

Answer 1

#y = mx + b#

We already know the slope, what remains is to find the #y#-intercept. To find the #y#-intercept, simply plug-in any known value for #x# and #y#.

#=> y = 3/7x + b# #=> 8 = 3/7(3) + b# #=> 8 = 9/7 + b# #=> 56 = 9 + 7b# #=> 47 = 7b# #=> 47/7 = b#

Hence, the equation of the line is

#y = 3/7x + 47/7#

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Answer 2

Hazel Anglin

To write the equation of a line with a given slope and containing a specific point, you can use the point-slope form of a linear equation:

(y - y_1 = m(x - x_1)),

where (m) is the slope and ((x_1, y_1)) is the given point.

Given the slope (m = \frac{3}{7}) and the point ((3, 8)), substitute these values into the point-slope form:

(y - 8 = \frac{3}{7}(x - 3)).

This is the equation of the line with slope (\frac{3}{7}) passing through the point ((3, 8)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.