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How do you write an equation of the line whose x-intercept is 2 and y intercept is -4?

Answer 1

Nathan Axel

#2x-y-4=0.#

We can use the following well-known Result :

If #a and b# are the #X and Y"-intercepts"# of a line, its eqn. is

#x/a+y/b=1#

In our Example, as #a=2, b=-4," so the eqn. follows :"#

#x/2+y/-4=1, i.e., 2x-y-4=0.#

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Answer 2

Jameson Allen

To write the equation of a line given its x-intercept and y-intercept, you can use the intercept form of the equation of a line, which is ( y = mx + b ), where ( m ) is the slope of the line and ( b ) is the y-intercept. Given the x-intercept ( (2, 0) ) and the y-intercept ( (0, -4) ), you can use these points to find the slope ( m ). The slope is given by ( m = \frac{{y_2 - y_1}}{{x_2 - x_1}} ). After finding the slope, substitute the slope and the y-intercept into the equation ( y = mx + b ) to get the equation of the line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.