How do you write an equation of the line that has slope 2/3 and passes through point (-6, 4)?

Answer 1

The equation you are looking for is: #y=2/3x+8#

In the general equation of a line: #y=ax+b# #a# is the slope, so the equation we are looking for can be written as: #y=2/3x+b#. Now we have to find such value for #b# to satisfy the second condition (line passes through (-6,4)). To do this we have to substitute #-6# for #x# and #4# for #y#.
#4=2/3*(-6)+b#
#4=-4+b#
#b=8#
Answer: The line has equation: #y=2/3x+8#
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Answer 2

The equation of the line with slope ( m ) passing through point ( (x_1, y_1) ) is given by:

[ y - y_1 = m(x - x_1) ]

Substituting the given values: [ y - 4 = \frac{2}{3}(x + 6) ]

Expanding and simplifying: [ y - 4 = \frac{2}{3}x + 4 ] [ y = \frac{2}{3}x + 8 ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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