How do you write an equation of the line in standard form that is Parallel to 5y-4x=15 and through (10,6)?

Answer 1

#4x-5y=10#

#5y-4x=15# has a slope of #4/5#
The slope-point form of a linear equation is #color(white)("XXX")(y-haty) = m(x-hatx)# #color(white)("XXXXXXX")#where #m# is the slope and #(hatx,haty)# is a point
For this example we have #color(white)("XXX")(y-6) = 4/5(x-10)#
Simplifying: #color(white)("XXX")y=4/5x-8+6#
#color(white)("XXX")5y=4x-10#
Standard form is #color(white)("XXX")Ax+By=C# with #A, B, C in ZZ, A>=0#
Converting to standard form: #color(white)("XXX")4x-5y=10#
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Answer 2

To write an equation of a line in standard form that is parallel to (5y - 4x = 15) and passes through the point ((10,6)), first determine the slope of the given line by rearranging the equation into slope-intercept form ((y = mx + b)). Then, since the line you're seeking is parallel, it will have the same slope. Use the point-slope form ((y - y_1 = m(x - x_1))) with the given point to find the equation. Finally, rewrite the equation in standard form ((Ax + By = C)) by manipulating the terms.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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