How do you write an equation of the line in standard form that is Parallel to 5y-4x=15 and through (10,6)?
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To write an equation of a line in standard form that is parallel to (5y - 4x = 15) and passes through the point ((10,6)), first determine the slope of the given line by rearranging the equation into slope-intercept form ((y = mx + b)). Then, since the line you're seeking is parallel, it will have the same slope. Use the point-slope form ((y - y_1 = m(x - x_1))) with the given point to find the equation. Finally, rewrite the equation in standard form ((Ax + By = C)) by manipulating the terms.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How do you find the slope that is perpendicular to the line #y= -1/2x + 4#?
- What is the slope of any line perpendicular to the line passing through #(-12,14)# and #(-13,1)#?

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