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How do you write an equation of the line given (3,-6) with slope -4/3?

Answer 1

Ethan Adkins

#3y=-4x-6#

The equstion of a straight line with slope #(m)# passing through the point #(x_1,y_1)# is given by:

#y-y_1 = m(x-x_1)#

In our example: #m=-4/3 and (x_1,y_1) = (3,-6)#

#:. (y-(-6)) = -4/3(x-3)#

#3(y+6) =-4(x-3)#

#3y+18 = -4x+12#

#3y = -4x+12-18#

#3y=-4x-6#

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Answer 2

Savannah Anderson

To write the equation of a line given a point (3, -6) and slope -4/3, you can use the point-slope form of a linear equation:

y - y1 = m(x - x1)

where (x1, y1) is the given point and m is the slope.

Substitute the given values into the formula:

y - (-6) = (-4/3)(x - 3)

Then, simplify the equation:

y + 6 = (-4/3)x + 4

Now, isolate y:

y = (-4/3)x + 4 - 6

y = (-4/3)x - 2

Therefore, the equation of the line is y = (-4/3)x - 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.