How do you write an equation of a point slope form passing through (-5,4) and parallel to the line whose equation is #4x-7y-8=0#?
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To write the equation of a line in point-slope form passing through a given point and parallel to another line, follow these steps:
- Find the slope of the given line by rearranging its equation into slope-intercept form (y = mx + b), where m is the slope.
- Since the new line is parallel, it will have the same slope as the given line.
- Use the slope and the given point (-5, 4) to write the equation in point-slope form (y - y1 = m(x - x1)), where (x1, y1) is the given point and m is the slope.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- What is the slope of any line perpendicular to the line passing through #(-6,1)# and #(7,-2)#?
- How do you name the point and slope given #y= -7.4 - 3/4 (x+1) #?

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