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How do you write an equation of a line with x-intercept=2 and y-intercept=4?

Answer 1

An x-intercept of 2 implies #(2,0)# is a point on the line A y-intercept of 4 implies #(0,4)# is a point on a line

The slope of the line joining #(2,0)# and #(0,4)# is #(Delta y)/(Delta x) = (4-0)/(0-2) = -2

Using the slope-intercept form of the equation #y = mx + b# where #m# is the slope and #b# is the y-intercept we have #y= -2x+4#

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Answer 2

Kennedy Adams

The equation of a line can be written in slope-intercept form as ( y = mx + b ), where ( m ) is the slope of the line and ( b ) is the y-intercept.

Given the x-intercept is 2 and the y-intercept is 4, we can use these points to find the slope:

[ \text{Slope} = \frac{{\text{Change in } y}}{{\text{Change in } x}} ]

[ \text{Slope} = \frac{{4 - 0}}{{0 - 2}} ]

[ \text{Slope} = \frac{4}{-2} ]

[ \text{Slope} = -2 ]

Now that we have the slope (( m = -2 )) and the y-intercept (( b = 4 )), we can write the equation of the line:

[ y = -2x + 4 ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.