How do you write an equation of a line with Slope = –5, passing through (–4, –2)?

Answer 1
The answer is : #y = -5x -22#.
The standard form of the equation of a line is : #y=mx+c#, where #m# is the slope.
Since you have a point #(x, y) = (-4, -2)# through which your line passes, you just have to solve the following equation in order to find #c# :
#y = -5x + c#
#-2 = (-5)*(-4) + c = 20 + c#
#-22 = c#
Therefore, the equation of your line is : #y = -5x -22#.
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Answer 2

To write the equation of a line with a given slope and passing through a point, you can use the point-slope form of a linear equation, which is ( y - y_1 = m(x - x_1) ). Substituting the given values of the slope ( m = -5 ) and the point ( (-4, -2) ), the equation becomes ( y - (-2) = -5(x - (-4)) ). Simplifying this equation yields ( y + 2 = -5(x + 4) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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