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How do you write an equation of a line with slope -5, passes through (2, -3)?

Answer 1

Avery Alexander

#y=-5x+7#

#y-y_1=m(x-x_1)#

Substitute the y value into #y_1#, the slope's gradient into m, and the x value into #x_1#. #y+3=-5(x-2)#

Multiply out the bracket. #y+3=-5x+10#

Take away 3 from both sides. #y=-5x+7#

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Answer 2

Eli Assouline

To write an equation of a line with slope -5 that passes through the point (2, -3), you can use the point-slope form of a linear equation:

(y - y_1 = m(x - x_1))

Substitute the given values into the equation:

(y - (-3) = -5(x - 2))

Simplify:

(y + 3 = -5(x - 2))

Distribute -5:

(y + 3 = -5x + 10)

Subtract 3 from both sides:

(y = -5x + 7)

Therefore, the equation of the line with slope -5 that passes through the point (2, -3) is (y = -5x + 7).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.