How do you write an equation of a line with slope 1 and y-intercept 1?

Answer 1

#y=x+1#

The equation of a line in #color(blue)"slope-intercept form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))# where m represents the slope and b, the y-intercept.

Here m = 1 and b = 1

#rArry=x+1" is the equation of the line"#
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Answer 2

#y=x+1#

Equation of a line with slope #m# and #y#-intercept #c# is
#y=mx+c#
and hence equation of a line with slope #1# and #y#-intercept as #1# is
#y=1xxx+1# or #y=x+1# graph{y=x+1 [-5.938, 4.06, -2.12, 2.88]}
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Answer 3

The equation of a line with slope ( m ) and y-intercept ( b ) can be written in slope-intercept form as: ( y = mx + b ). For a line with slope 1 and y-intercept 1, the equation would be ( y = x + 1 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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