How do you write an equation of a line with center at the origin and #r=sqrt7#?

Answer 1

#x^2+y^2=7#

I am assuming you require the equation of a circle since the question gives centre and radius.

The standard form of the #color(blue)"equation of a circle"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))# where (a ,b) are the coordinates of the centre and r, the radius.

#"here the centre "=(0,0)" and "r=sqrt7#

#rArr(x-0)^2+(y-0)^2=(sqrt7)^2#

simplifying gives.

#x^2+y^2=7larrcolor(red)" equation of circle"#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Wyatt Anderson

To write the equation of a line with center at the origin and radius ( r = \sqrt{7} ), you can use the formula for the equation of a circle centered at the origin:

[ x^2 + y^2 = r^2 ]

Substitute ( r = \sqrt{7} ) into the equation:

[ x^2 + y^2 = (\sqrt{7})^2 ]

Simplify:

[ x^2 + y^2 = 7 ]

So, the equation of the line with center at the origin and radius ( r = \sqrt{7} ) is ( x^2 + y^2 = 7 ).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.