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How do you write an equation of a line with (-2,3); m=-1?

Answer 1

Isaiah Anthony

#y=-x+1#

Slope-intercept form of a line: #y=mx+b#, where m is the slope and b is the y-intercept

Put -1 in for m:

#y=-x+b#

To solve for b, put in the point #(-2, 3)#.

#3=-(-2)+b#

#3=2+b#

#b=1#

The equation is #y=-x+1#

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Answer 2

Jameson Allen

The equation of the line can be written in point-slope form as ( y - y_1 = m(x - x_1) ), where ( (x_1, y_1) ) is the given point and ( m ) is the slope. Substituting the values ( x_1 = -2 ), ( y_1 = 3 ), and ( m = -1 ) into the equation gives:

[ y - 3 = -1(x - (-2)) ] [ y - 3 = -1(x + 2) ] [ y - 3 = -x - 2 ] [ y = -x + 1 ]

So, the equation of the line with a slope of -1 passing through the point (-2, 3) is ( y = -x + 1 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.