Home > Algebra > Write an Equation Given the Slope and a Point

How do you write an equation of a line that passes through (4,-3) and has a slope of -3/4?

Answer 1

Hazel Anglin

#4y+3x=0#

Using the point gradient form: #(y-y_1)=m(x-x_1)#,

your gradient is #-3/4# your point is #(4,-3)#

Equation:

#(y+3)=-3/4(x-4)#

#4y+12=-3x+12#

#4y+3x=0#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Savannah Anderson

The equation of the line is y = -3/4x + 15/4.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 3

Eva Abramson

The equation of a line in slope-intercept form is given by ( y = mx + b ), where ( m ) is the slope of the line and ( b ) is the y-intercept (the point where the line crosses the y-axis).

Given that the slope ( m = -\frac{3}{4} ) and the point ( (4, -3) ) lies on the line, we can substitute these values into the equation to find ( b ).

( -3 = -\frac{3}{4} \times 4 + b )

( -3 = -3 + b )

( b = 0 )

So, the equation of the line is ( y = -\frac{3}{4}x ).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.