How do you write an equation of a line passing through (6, 1), perpendicular to #4y - 2 = 3x#?

Answer 1

#3y+4x=27#

#4y-2=3x# #4y=3x+2# #y=(3/4)x+(1/2)# Slope of the line #m1=3/4# Slope of perpendicular line #m2=-1/(m1)=-(1/(3/4))=-(4/3)# Equation of the perpendicular line #(y-1)=-(4/3)(x-6)# #3y-3=-4x+24# #3y+4x=27#

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Answer 2

Eva Abramson

To write the equation of a line passing through (6, 1) and perpendicular to 4y - 2 = 3x, first find the slope of the given line, then find the negative reciprocal of that slope to get the slope of the perpendicular line. After that, use the point-slope form of the equation of a line, y - y₁ = m(x - x₁), where (x₁, y₁) is the given point and m is the slope. Finally, substitute the values into the equation to find the equation of the perpendicular line passing through (6, 1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.