How do you write an equation of a line passing through (3, 2), perpendicular to # y=5x + 2#?
Find the negative reciprocal of the slope and, using our point, write the equation in slope-intercept form.
Now, let's plug in our value and solve!
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To write an equation of a line passing through the point (3, 2) and perpendicular to the line (y = 5x + 2), you need to find the negative reciprocal of the slope of the given line and then use the point-slope form of a linear equation.
The slope of the given line is 5, so the negative reciprocal of 5 is (-\frac{1}{5}).
Now, using the point-slope form with the given point (3, 2) and the slope (-\frac{1}{5}), the equation of the perpendicular line is:
[y - y_1 = m(x - x_1)] [y - 2 = -\frac{1}{5}(x - 3)]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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