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How do you write an equation of a line going through (1,2) (-1,2)?

Answer 1

Genesis Allen

#y=2 #

#"Equation of a straight line parallel to the X-axis"#

#"First find the slope of the line passing through the two "# #"points (1,2) and (-1,2)"#

#slope=(y_2-y_1)/(x_2-x_1)#

#slope =((2-2))/(((-1)-1))#

#slope =0 #

#y=a*x+b#

# "the point "(1,2)" is a point on the line."#

#y=0*(1)+2#

#y=2 " is the equation of a straight line parallel to the X-axis."#

graph{0*x+2 [-2.662, 2.74, -0.276, 2.423]}

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Answer 2

Eli Assouline

To write the equation of a line going through the points (1,2) and (-1,2):

Find the slope using the formula: slope (m) = (change in y) / (change in x)
Substitute the coordinates of the points into the slope formula: m = (2 - 2) / (1 - (-1))
Simplify: m = 0 / 2 = 0
Since the slope is 0, the line is horizontal.
Use the point-slope form of a linear equation: y - y₁ = m(x - x₁)
Substitute the slope (m) and one of the points (x₁, y₁) into the equation: y - 2 = 0(x - 1)
Simplify: y - 2 = 0
Add 2 to both sides: y = 2

So, the equation of the line going through the points (1,2) and (-1,2) is y = 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.