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How do you write an equation of a line given point (-6, 3) and has slope 2?

Answer 1

#y=2x+15#

The equation of a line in #color(blue)"point-slope form"# is

#color(red)(bar(ul(|color(white)(a/a)color(black)(y-y_1=m(x-x_1))color(white)(a/a)|)))# where m represents the slope and # (x_1,y_1)" a point on the line"#

here m = 2 and #(x_1,y_1)=(-6,3)#

substitute these values into the equation

#y-3=2(x-(-6))#

#rArry-3=2(x+6)rArry-3=2x+12#

#rArry=2x+15larr" in slope-intercept form"#

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Answer 2

Eva Abramson

To write the equation of a line given a point (-6, 3) and a slope of 2, you can use the point-slope form of a linear equation, which is ( y - y_1 = m(x - x_1) ), where (x1, y1) is the given point and m is the slope.

Plugging in the values (-6, 3) for (x1, y1) and 2 for m, the equation becomes ( y - 3 = 2(x + 6) ). Simplifying further gives ( y - 3 = 2x + 12 ). To get the equation in slope-intercept form (y = mx + b), add 3 to both sides to isolate y, resulting in ( y = 2x + 15 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.