Home > Algebra > Write an Equation Given the Slope and a Point

How do you write an equation of a line given point (-2,5/2) and slope -1/2?

Answer 1

Eva Abramson

#y=-1/2x+3/2#

You can use the general equation:

#y-y_0=m(x-x_0)#

where the point #(x_0,y_0)# will be substituted by #(-2,5/2)# and m is the slope #-1/2#

So your equation will be:

#y-5/2=-1/2(x+2)#

#y=-1/2x-1+5/2#

#y=-1/2x+3/2#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Savannah Anderson

To write the equation of a line given a point ((-2, \frac{5}{2})) and a slope of (-\frac{1}{2}), use the point-slope form of a line equation, which is (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is the given point.

Substitute (m = -\frac{1}{2}), (x_1 = -2), and (y_1 = \frac{5}{2}) into the equation:

[y - \frac{5}{2} = -\frac{1}{2}(x - (-2))]

[y - \frac{5}{2} = -\frac{1}{2}(x + 2)]

To simplify, you can distribute the slope and then rearrange the equation into slope-intercept form (y = mx + b), if needed. Let's simplify the given equation.The simplified equation of the line given the point ((-2, \frac{5}{2})) and slope (-\frac{1}{2}) is (y = -\frac{1}{2}x + \frac{3}{2}).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.