How do you write an equation of a line given (5, -2); (-16, 4)?

Answer 1

See a solution process below:

First, we need to determine the slope of the line. The slope can be found by using the formula: #m = (color(red)(y_2) - color(blue)(y_1))/(color(red)(x_2) - color(blue)(x_1))#
Where #m# is the slope and (#color(blue)(x_1, y_1)#) and (#color(red)(x_2, y_2)#) are the two points on the line.

Substituting the values from the points in the problem gives:

#m = (color(red)(4) - color(blue)(-2))/(color(red)(-16) - color(blue)(5)) = (color(red)(4) + color(blue)(2))/(color(red)(-16) - color(blue)(5)) = 6/-21 = -2/7#
We can now use the point-slope formula to write an equation for the line. The point-slope form of a linear equation is: #(y - color(blue)(y_1)) = color(red)(m)(x - color(blue)(x_1))#
Where #(color(blue)(x_1), color(blue)(y_1))# is a point on the line and #color(red)(m)# is the slope.

Substituting the slope we calculated and the values from the first point in the problem gives:

#(y - color(blue)(-2)) = color(red)(-2/7)(x - color(blue)(5))#
#(y + color(blue)(2)) = color(red)(-2/7)(x - color(blue)(5))#

We can also substitute the slope we calculated and the values from the second point in the problem giving:

#(y - color(blue)(4)) = color(red)(-2/7)(x - color(blue)(-16))#
#(y - color(blue)(4)) = color(red)(-2/7)(x + color(blue)(16))#
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Answer 2

To write the equation of a line given two points, you can follow these steps:

  1. Find the slope ( m ) using the formula: [ m = \frac{{y_2 - y_1}}{{x_2 - x_1}} ]

  2. Use one of the given points and the slope to write the equation in point-slope form: [ y - y_1 = m(x - x_1) ]

  3. If necessary, simplify the equation into slope-intercept form: [ y = mx + b ]

Using the points (5, -2) and (-16, 4):

  1. Calculate the slope: [ m = \frac{{4 - (-2)}}{{-16 - 5}} = \frac{{4 + 2}}{{-16 - 5}} = \frac{6}{-21} = -\frac{2}{7} ]

  2. Choose one of the points, let's say (5, -2), and substitute it into the point-slope form: [ y - (-2) = -\frac{2}{7}(x - 5) ]

  3. Simplify if needed: [ y + 2 = -\frac{2}{7}(x - 5) ] [ y + 2 = -\frac{2}{7}x + \frac{10}{7} ] [ y = -\frac{2}{7}x + \frac{10}{7} - 2 ] [ y = -\frac{2}{7}x + \frac{10}{7} - \frac{14}{7} ] [ y = -\frac{2}{7}x - \frac{4}{7} ]

So, the equation of the line passing through the points (5, -2) and (-16, 4) is ( y = -\frac{2}{7}x - \frac{4}{7} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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