How do you write an equation of a circle with center at origin and r=3?

Answer 1

The standard form is:
#(x - h)^2 + (y - k)^2 = r^2#
where (h,k) is the center and r is the radius.
Your center is at #(0,0)# and the radius, #r = 3#
#(x - 0)^2 + (y - 0)^2 = 3^2#

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Answer 2

The equation of a circle with its center at the origin and a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). So, for a circle with a center at the origin and a radius of 3, the equation would be ( x^2 + y^2 = 3^2 ), which simplifies to ( x^2 + y^2 = 9 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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