# How do you write an equation of a circle with center at (0,0), d=12?

The standard Cartesian form for the equation of a circle is:

where (h,k) is the center and r is the radius.

Use the diameter to compute the radius:

Substitute the center and the radius into equation [1]:

Equation [2] is the answer.

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The equation of a circle with center at ((0,0)) and diameter (d=12) is:

[x^2 + y^2 = 36]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- A triangle has corners at #(2 ,3 )#, #(1 ,9 )#, and #(6 ,8 )#. What is the radius of the triangle's inscribed circle?
- Write the equation of a circle with a radius of 10 and a center of (-2,5)?
- A triangle has sides with lengths of 8, 4, and 6. What is the radius of the triangle's inscribed circle?
- A circle's center is at #(4 ,0 )# and it passes through #(6 ,9 )#. What is the length of an arc covering #(5pi ) /3 # radians on the circle?
- A circle has a chord that goes from #( pi)/3 # to #(5 pi) / 12 # radians on the circle. If the area of the circle is #48 pi #, what is the length of the chord?

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