How do you write an equation in standard form passing through points (8,5) & (0,-4)?

Answer 1

9x-8y= 32 would be the equation.

First we get the slope of the line = #(5+4)/(8-0)# = #9/8# Now,we can write the point slope form of the line using the point (8,5) as y-5=#9/8# (x-8). Now, simplify by multiplying both sides by 8 to have 8(y-5) = 9(x-8) Or, 8y-40 = 9x-72 , Or 9x-8y= 72-40 =32. Standard form is thus 9x-8y=32

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Answer 2

Eli Assouline

To write an equation in standard form passing through points (8,5) and (0,-4), follow these steps:

Find the slope (m) using the formula: ( m = \frac{{y_2 - y_1}}{{x_2 - x_1}} ).
Choose one of the points and the slope to write the equation in point-slope form: ( y - y_1 = m(x - x_1) ).
Substitute the values of the chosen point and the slope into the point-slope form.
Simplify the equation and rewrite it in standard form: ( Ax + By = C ), where A, B, and C are integers and A is positive.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you write an equation in standard form passing through points (8,5) &amp; (0,-4)?

How do you write an equation in standard form passing through points (8,5) & (0,-4)?