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How do you write an equation in standard form given that the line passes through (-7,-2) with slope -3?

Answer 1

Savannah Anderson

Equation in standard form: y = -3x + b.

Find b by writing that the line passing at point (-7, -2):

-2 = -3(-7) + b -> b = -21 - 2 = -23.

y = -3x - 23.

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Answer 2

Eva Adamson

To write an equation in standard form given that the line passes through (-7,-2) with slope -3, you can use the point-slope form of a linear equation, which is y - y₁ = m(x - x₁), where (x₁, y₁) is the given point and m is the slope. Substituting the given values into the equation, we get: y - (-2) = -3(x - (-7)). Simplifying, we have: y + 2 = -3(x + 7). To write the equation in standard form, we distribute the -3 and then rearrange terms to get the form Ax + By = C, where A, B, and C are constants and A is positive. So, y + 2 = -3x - 21 becomes 3x + y = -23. Thus, the equation in standard form is 3x + y = -23.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.