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How do you write an equation in standard form given point (3,0) and slope 5?

Answer 1

y = 5x - 15

The equation of a line in #color(blue)"point-slope form"# is

#color(red)(|bar(ul(color(white)(a/a)color(black)(y-b=m(x-a))color(white)(a/a)|)))# where m represents the slope and (a ,b) a point on the line.

here m = 5 and (a ,b) = (3 ,0)

Substitute these values into the equation and simplify.

y - 0 = 5 (x - 3) → y = 5x - 15

Thus #color(red)(|bar(ul(color(white)(a/a)color(black)(y=5x-15)color(white)(a/a)|)))# is the equation

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Answer 2

Eli Assouline

To write an equation in standard form given a point ((3,0)) and slope (5), you can use the point-slope form of a linear equation: (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is the given point.

Substituting the given values, the equation becomes (y - 0 = 5(x - 3)).

Simplify: (y = 5x - 15).

To convert this equation into standard form, move all terms to one side to make the equation equal to zero:

[5x - y - 15 = 0]

So, the equation in standard form is (5x - y - 15 = 0).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.