How do you write an equation in standard form given a line that passes through (5,8) and (2,2)?

Answer 1

See a solution process below:

First we need to determine the slope of the line. The slope can be found by using the formula: #m = (color(red)(y_2) - color(blue)(y_1))/(color(red)(x_2) - color(blue)(x_1))#
Where #m# is the slope and (#color(blue)(x_1, y_1)#) and (#color(red)(x_2, y_2)#) are the two points on the line.

Substituting the values from the points in the problem gives:

#m = (color(red)(2) - color(blue)(8))/(color(red)(2) - color(blue)(5)) = (-6)/-3 = 2#
We can now use the point slope formula to write an equation for the line. The point-slope form of a linear equation is: #(y - color(blue)(y_1)) = color(red)(m)(x - color(blue)(x_1))#
Where #(color(blue)(x_1), color(blue)(y_1))# is a point on the line and #color(red)(m)# is the slope.

Substituting the slope we calculated and the values from either point in the problem (I will use the values from the second point) into the formula gives:

#(y - color(blue)(2)) = color(red)(2)(x - color(blue)(2))#
We can now solve this equation for the Standard Form of a Linear Equation. The standard form of a linear equation is: #color(red)(A)x + color(blue)(B)y = color(green)(C)#
Where, if at all possible, #color(red)(A)#, #color(blue)(B)#, and #color(green)(C)#are integers, and A is non-negative, and, A, B, and C have no common factors other than 1
#y - color(blue)(2) = (color(red)(2) xx x) - (color(red)(2) xx color(blue)(2))#
#y - color(blue)(2) = 2x - 4#
#-color(red)(2x) + y - color(blue)(2) + 2 = -color(red)(2x) + 2x - 4 + 2#
#-2x + y - 0 = 0 - 2#
#-2x + y = -2#
#color(red)(-1)(-2x + y) = color(red)(-1) xx -2#
#(color(red)(-1) xx -2x) + (color(red)(-1) xx y) = 2#
#2x + (-1y) = 2#
#color(red)(2)x - color(blue)(1)y = color(green)(2)#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

First, find the slope using the formula: ( m = \frac{{y_2 - y_1}}{{x_2 - x_1}} ). Then, use the point-slope form: ( y - y_1 = m(x - x_1) ). Finally, rearrange the equation into standard form: ( Ax + By = C ).

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7