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How do you write an equation in standard form given (-3, -3), (7,2)?

Answer 1

#x-2y=3#

Just so we know what our target is: Standard form for a linear equation is #color(white)("XXX")Ax+By=C#

Step 1: write the equation in slope-point form

slope: #m=(Delta y)/(Delta x) = (2-(-3))/(7-(-3)) = 5/10 = 1/2#

slope point form with slope #m# through a point #(barx,bary)# is #color(white)("XXX")(y-bary) = m(x-barx)# Using the above slope and #(-3,-3)# for #(barx,bary)# #color(white)("XXX")y+3 = 1/2(x+3)#

Step 2: convert from slope-point to standard form

#y+3=1/2(x+3)#

#rarr 2y+6 = x+3#

#rarr x-2y=3##color(white)("XXX")#or if you want to be picky: #1x+(-2)y=3#

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Answer 2

Jameson Allen

To write an equation in standard form given the points (-3, -3) and (7, 2), we first find the slope using the formula: slope (m) = (change in y) / (change in x). Then, we use one of the points along with the slope to find the y-intercept (b). Finally, we substitute the values of slope (m) and y-intercept (b) into the standard form equation y = mx + b and rearrange it to standard form Ax + By = C.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.