How do you write an equation in standard form for a line which passes through points (-10,3) and (-2,-5)?

Answer 1
The equation of the line is #y = -x-7#.

To find this, note that we are looking for an equation of the form:

#y = mx+c#
for some constant slope #m# and intercept #c#.
The slope #m# can be calculated as:
#m = (Delta y)/(Delta x) = (-5-3)/(-2-(-10)) = (-8)/8 = -1#
where #Delta y# means the change in #y# and #Delta x# means the change in #x#.
So we now know that #y = mx+c = (-1)x+c = -x+c#.
Add #x# to both ends to get #y+x=c#. Subsitute in either of our points to calculate #c#. Let us use #x=-10# and #y=3#:
#c=y+x=3+(-10)=3-10=-7#.
So #m = -1# and #c = -7#, giving #y=-x-7#.
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Answer 2

To write an equation in standard form for a line passing through two points (-10,3) and (-2,-5), follow these steps:

  1. Calculate the slope using the formula: slope (m) = (y2 - y1) / (x2 - x1)
  2. Substitute the coordinates of one of the points and the slope into the point-slope form of a linear equation: y - y1 = m(x - x1)
  3. Once you have the equation in point-slope form, rearrange it to standard form, which is Ax + By = C, where A, B, and C are integers and A is positive.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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