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How do you write an equation in standard form for a line which passes through (3, 6) and (0, -3) ?

Answer 1

#y=3x-3#

Equation of a line is #y=mx+c# The first point #y=6, x=3# gives #6=3m+c# The second point #y=-3, x=0# gives #-3=c# Substituting for c for the first point gives #m=3#

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Answer 2

Eva Adamson

To write the equation of a line in standard form passing through the points (3, 6) and (0, -3), you first find the slope using the formula:

m = (change in y) / (change in x)

Then, using the point-slope form equation:

y - y₁ = m(x - x₁)

You substitute the values of one of the given points and the slope to find the equation. Finally, rearrange the equation to standard form, Ax + By = C.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.