How do you write an equation in standard form for a line passing through (2,9) and (1,3)?

Answer 1
Given two points #(x_1,y_1)# and #(x_2,y_2)# The slope can be calculated as #m= (y_1-y_2)/(x_1-x_2)# For the points given #(2,9)# and #(1,3)# this gives #m= 6#
We can then use this slope plus either one of the given points (I'm going to use #(1,3)# but it shouldn't make any difference) to write the equation in slope-point form #y-y_2 = m(x-x_2)# or for our values #y-3 = 6(x-1)#
Standard form for a line is #Ax+By=C# so we shift some values around to get
#(-6)x+(1)y = -3#
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Answer 2

To write an equation in standard form for a line passing through (2,9) and (1,3), first find the slope using the formula: ( m = \frac{{y_2 - y_1}}{{x_2 - x_1}} ). Then, use the slope-intercept form ( y = mx + b ) to find the y-intercept ( b ). Once you have the slope and y-intercept, substitute them into the standard form equation ( Ax + By = C ), rearranging if necessary.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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