How do you write an equation in standard form for a line passing through (2, 5) with a slope of 3?

Answer 1

Since the formula of a line given a point and the slope is:

#y-y_p=m(x-x_p)#,
#y-5=3(x-2)rArry=3x-1#.
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Answer 2

To write an equation in standard form for a line passing through (2, 5) with a slope of 3, you can use the point-slope form: y - y₁ = m(x - x₁). Substitute the given point (2, 5) and slope m = 3 into the equation. This gives you: y - 5 = 3(x - 2). Expand and simplify to get the equation in slope-intercept form: y - 5 = 3x - 6. Next, move the constant to the other side: y = 3x - 6 + 5 = 3x - 1. Finally, rewrite the equation in standard form: -3x + y = -1. Therefore, the equation in standard form for the line passing through (2, 5) with a slope of 3 is -3x + y = -1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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